SELECT w.name, w.url, a.count, a.date FROM Websites AS w, access_log AS a WHERE a.site_id=w.id and w.name="菜鸟教程";
执行输出结果:
不带别名的相同的 SQL 语句:
实例
SELECT Websites.name, Websites.url, access_log.count, access_log.date FROM Websites, access_log WHERE Websites.id=access_log.site_id and Websites.name="菜鸟教程";